Y=log(1-x^2/1 x^2) find dy/dx 997759-Log x y solve for x

If Y X 2 1 Log 1 X 1 1 X 2 Find Dy Dx Sarthaks Econnect Largest Online Education Community

Find d2y/dx2 where y=log(x^2/e^2) y=log(x 2 /e 2 ) diff wr to x , we get dy/dx=1/(x 2 /e 2 ) (2x/e 2 ) =2/x diff wr to x again d 2 y/dx 2 =2/x 2 Thank 1 Answer Shwetank Mauria Please see below Explanation Here we have to use implicit differentiation As log(xy) = x2 y2 or logx logy = x2 y2 assuming base is

Log x y solve for x

Log x y solve for x-Find dy/dx y^2=1/(1x^2) Differentiate both sides of the equation Differentiate the left side of the equation Tap for more steps Differentiate using the chain rule, which states that is where andLet's simplify it First dy/dx = (y/x 1)/ (y/x 1) Taking y = vx dy/dx = v xdv/dx Therefore, dx/x = (v 1)dv / (v^2 1) Integrating we get log (1/x) logc = arctan (y/x) 1/2 log How to show

If Y Log X X 2 A 2 Then Prove That X 2 A 2 D 2ydx 2 X Dydx 0

Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more asked in Derivatives by Shyam01 (507k points) closed by Shyam01 If y = (1 1/x2)/ (1 1/x2), then dy/dx is limits derivatives class11 1 Answer 1 vote I'll start with the second one for you Take the natural logarithm of both sides Now for the second I would differentiate term by term Let t = xy and u = yx Then lnt = ln(xy) and lnu

Explanation Given that x1 2 y1 2 = a1 2 differentiating above equation wrt x on both sides as follows d dx (x1 2 y1 2) = d dx (a1 2) 1 2 x1 2 −1 1 2 y1 2−1 dy dx = 0 x− 1 2 y− 1 2 dy dx = 0 1 √x 1 √y dy dx = 0 1 √y dy dx = − 1 √xFind dydx, if x = 1u2,y=log(1u2) Maharashtra State Board HSC Commerce 12th Board Exam Question Papers 210 Textbook Solutions MCQ Online Tests 99 Find `"dy"/"dx"`, if x Best answer Answer is C 1/√x2a2 Given that y = loge(x√x2 a2 x 2 a 2) Differentiating with respect to x, we get ← Prev Question Next Question → Free JEE Main Mock